if A={1,2,3} B={2,3,4} THEN
a)A×B=B×A
b)A×B=0
C)A×B≠B×A
d)(A×B)∩(B×A)≠0
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c) and d) both are correct.
A X B ≠ B X A as there are different elements in them: 1 , 4...
A X B ∩ B X A = { (2,2) , (3,3) } ≠ ∅
A X B ≠ B X A as there are different elements in them: 1 , 4...
A X B ∩ B X A = { (2,2) , (3,3) } ≠ ∅
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