Question

if A=1,2,3 B2, 3,4 C=3,4,5 prove that distributive law ​

Answer 1

Answer:

[(x ∈ A) and (y ∈ B)] or [(x ∈ A) and (y ∈ C)] ( by a distributive law of logic) ... on A that contain none of (1,2),(3,4),(5,6) is 297. ... Then, fc = {(a,1),(b,2),(c,3)} is not a function because it.