Question

if a=1+√2 and b=1-√2 then the value of a2+b 2 is​

Answer 1

Answer:

On substituting the value of

$(1 + \sqrt{2} \times 1 + \sqrt{2} ) \: + (1 - \sqrt{2} \times 1 - \sqrt{2} ) \\(1 + 2 + 2 \sqrt{2} ) + (1 + 2 - 2 \sqrt{2} ) \\ 1 + 2 + 2 \sqrt{2} + 1 + 2 - 2 \sqrt{2} \\ 1 + 2 + 1 + 2 \\ 4 + 2 \\ 6$