Question

if a^1/2+b^1/2-c^1/2=0 then find the value of (a+b-c)^2

Answer 1

HELLO......FRIEND!!

THE ANSWER IS HERE,

$= > \: \sqrt{a} + \sqrt{b} - \sqrt{c} = 0$

$= > \: \sqrt{a} + \sqrt{b} = \sqrt{c}$

Squaring on both sides,

$= > \: { (\sqrt{a} + \sqrt{b} })^{2} = ({ \sqrt{c} })^{2}$

$= > \: a + b + 2 \sqrt{ab} = c$

$= > \: a + b - c = - 2 \sqrt{ab}$
Squaring on both sides,

$= > \: {(a + b - c)}^{2} =( { - 2 \sqrt{ab} })^{2}$

$= > \: 4ab$


:-)Hope it helps u.

Answer 2

Hi Friend !!!

==============

=> √a + √b - √c = 0

=> √a+√b = √c

squaring on both sides

=> (√a + √b)² = √c²

a + b +2√ab = c

a+b-c = -2√ab

(a+b-c)² = (-2√ab)²

(a+b-c)² = 4ab

Hope it helps u:-)