Math, asked by FieryAnish, 10 months ago

If A = (1, 2), B = (3,-2) and P moves in the plane such that AP+BP = 7 then the locus of P has two
axes of symmetry. Their equations are
1) x - 2y + 3 =0.2x + y = 4
2) 2x + y = 4, x-2y=2
3) x-2y = 2.x - y + 1 = 0
4) x-2y = 7, 2x + y = 4

Answers

Answered by tiwarishivam951
0

Answer:

2 option is correct

2x+y=4,x-2y=2

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