If A(1,2), B(4,3) and C(6,6) are the vertices of parallelogram ABCD, find the coordinates of vertex D.
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Answer:
X=3, Y=5
Step-by-step explanation:
Given ║gm ABCD with vertices A(1,2), B(4,3) & C(6,6)
let the point D be (x,y).Join AC & BD
In a parallelogram, diagonals bisect each other.
∴ mid-point of AC =mid-point of BD.....................eq.1
By midpoint formula,
mid-point of AC= 1+6/2 , 2+6/2
=7/2 , 8/2
=7/2 , 4
by eq.1; again by midpoint formula,
mid-point of BD=4+x/2=7\2 , 3+y/2=4
by cross-multiplying; 4+x=7[2 get cancelled] , 3+y=8
=x=7-4 , y=8-3
=x=3, y=5
∴ vertices of D are (3,5)
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