If a(1,2) b(4,y) c(x,6) d(3,5) are thr vertices of a parallelogram taken in order find x and y
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Let A,B,C and D be the points (1,2) (4,y), (x,6) and (3,5) respectively.
Mid point of diagonal AC is
and Mid point of Diagonal BD is
Since the diagonals of a parallelogram bisect each other, the mid point of AC and BD are same.
∴ x+1/2 = 7/2 and 4 = 5+y/2
⇒ x + 1 = 7 and 5 + y = 8
⇒ x = 6 and y = 3
Hope this helped
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