if a= {1.2} b = {x:xenand×2_9=6} find a×b
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Step-by-step explanation:
A = {x:x is a natural number and multiple of 3} = {3,6,9…}
As, B = {x:x is a natural number less than 6} = {1,2,3,4,5,6}
A∪B = {1,2,4,5,3,6,9,12…}
∴, A∪B = {x:x=1,2,4,5 or a multiple of 3}
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