if a= 1-√2,find (a-1/a)3
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a=1-√2
1/a=1/(1-√2)
or, 1/a=(1+√2)/(1-√2)(1+√2)
or, 1/a=(1+√2)/(1-2)
or, 1/a=-(1+√2)
∴, (a-1/a)³=[(1-√2)-{-(1+√2)}]³=(1-√2+1+√2)³=2³=8
1/a=1/(1-√2)
or, 1/a=(1+√2)/(1-√2)(1+√2)
or, 1/a=(1+√2)/(1-2)
or, 1/a=-(1+√2)
∴, (a-1/a)³=[(1-√2)-{-(1+√2)}]³=(1-√2+1+√2)³=2³=8
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