Question

. If a+1=-2b, show that 1+a3+8b3=6ab.​

Answer 1

Answer:

Hi ,

a + 2b + 3c = 0 ---( 1 )

a + 2b = - 3c ---( 2 )

( a + 2b )³ = ( - 3c )³

a³ + ( 2b )³ + 3 × a × 2b ( a + 2b ) = - 27c³

a³ + 8b³ + 27c³ + 6ab × ( - 3c ) = 0

[from ( 2 ) ]

a³ + 8b³ + 27c³ - 18abc = 0

a³ + 8b³ + 27c³ = 18abc

Hence proved .

I hope this helps you.

:)

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