Question

if a=1/3-√11and b=1/a then find a²-b² ​

Answer 1

Given, (a+b)=7, ab=10

Squaring both sides

⇒(a+b)2=72

⇒a2+b2+2ab=49

⇒a2+b2=49−2(10)

⇒a2+b2=29

Now,

(a−b)2=a2+b2−2ab

     =29−2(10)

     =29−20

     =9

∴a−b=9=+3