Math, asked by prathapalav0208, 6 months ago

If A = 1
3
2
2
and B= (1 - I
1 - 2 - 3
1
1 - 1
Examine whether AB has inverse or
not.
-
HE

Answers

Answered by neelamjyoti653

AnswerAB=[

AB=[ 1

AB=[ 11

AB=[ 11 2

AB=[ 11 2−2

AB=[ 11 2−2 3

AB=[ 11 2−2 33

AB=[ 11 2−2 33 ]

AB=[ 11 2−2 33 ] ⎣

AB=[ 11 2−2 33 ] ⎣⎢

AB=[ 11 2−2 33 ] ⎣⎢⎢

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 1

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 11

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −1

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤ =[

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤ =[ 6

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤ =[ 62

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤ =[ 62 −3

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤ =[ 62 −3−11

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤ =[ 62 −3−11 ]

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤ =[ 62 −3−11 ]∣AB∣=−66×6=−60

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤ =[ 62 −3−11 ]∣AB∣=−66×6=−60∵∣AB∣

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤ =[ 62 −3−11 ]∣AB∣=−66×6=−60∵∣AB∣

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤ =[ 62 −3−11 ]∣AB∣=−66×6=−60∵∣AB∣=0∴ Inverse of AB exists

AB=[ 11 2−2 33 ] ⎣⎢⎢⎡ 111 −12−2 ⎦⎥⎥⎤ =[ 62 −3−11 ]∣AB∣=−66×6=−60∵∣AB∣=0∴ Inverse of AB existsAnswer By

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