Question

If A= 1/(3-2 root 2) , B= 1/(3+2 root 2) Then, find the value of a^2 +b^2
Don't say anything else pls

Answer 1

Answer:

Here value of ( a3 + b3 = 198 )

Answer 2

Step-by-step explanation:

$A= \frac{1}{3 - 2 \sqrt{2} } \\ B= \frac{1}{3 + 2 \sqrt{2} } \\ \\ A²+B²=( \frac{1}{3-2 \sqrt{2} } )² + (\frac{1}{3 + 2 \sqrt{2} } )² \\ = \frac{(3+2 \sqrt{2})²+(3-2 \sqrt{2})² }{(3-2 \sqrt{2})²(3+2 \sqrt{2})² } \\ = \frac{9 + 12 \sqrt{2} + 8 + 9 - 12 \sqrt{2} + 8}{(9 - 8)²} \\ = \frac{18+16}{1} \\ = 34$