Question

If a = 1/3-√8 and b = 1/3+√8. Find the value of a^2​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Here, a=1/3–√8

then,

a^(2)= [{1/3–√8}]^2

={1/3}^2 –2*1/3*√8 +{√8}^2

=1/9 – (4*√2)/3 + 8

={1–12√2 +72}/9

={73–12√2}/9