Question

if a=1/3-√8 and b=1/3+√8 find value of (a+b) ^2​

Answer 1

$a = \frac{1}{3} - \sqrt{8} \: \: \: b = \frac{1}{3} + \sqrt{8} \\ (a + b)^{2} = { ((\frac{1}{3} - \sqrt{8} ) + ( \frac{1}{3} + \sqrt{8} )}) ^{2} \\ = (\frac{1}{3} - \sqrt{8} + \frac{1}{3} + \sqrt{8} ) ^{2} \\ = (\frac{2}{3} ) ^{2} = \frac{4}{9} (ans)$

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Answer 2

Answer:

hyy here is the answer to your questions.....(^^)