If A (-1,3) ,B (1,-1) ,C (5,1) are vertices of a triangle ABC. What is the length of the median through vertex A ..
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here's your answer dude.
Let A(-1;3)=(x1,y1)
& B(1,-1)=(x2,y2)
& C(5,-1)=(x3,y3)
Meadian=?
therefore, median formula is x+y÷2
in case of A&B
x1+x2÷2 or y1+y2÷2
-1+1÷2 or 3- (-1)÷2
=0 or =2
(x,y)=(0,2)
in case of A&C
x1+y3÷2 or y1+y3÷2
-1+5÷2 or 3+(-1)÷2
=2 or =1
so,(x,y)=(2,1)
therefore in case of A&B (x,y)=(0,2)
& in case of A&C (x,y)=(2,1)
hope it helpz plz mark as brainliest.
Let A(-1;3)=(x1,y1)
& B(1,-1)=(x2,y2)
& C(5,-1)=(x3,y3)
Meadian=?
therefore, median formula is x+y÷2
in case of A&B
x1+x2÷2 or y1+y2÷2
-1+1÷2 or 3- (-1)÷2
=0 or =2
(x,y)=(0,2)
in case of A&C
x1+y3÷2 or y1+y3÷2
-1+5÷2 or 3+(-1)÷2
=2 or =1
so,(x,y)=(2,1)
therefore in case of A&B (x,y)=(0,2)
& in case of A&C (x,y)=(2,1)
hope it helpz plz mark as brainliest.
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