Question

If A(1,3) ,B (-1,2) ,C(2,5),D (x,4) are the vertices of a llgm ABCD find the value of x

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

value of 'x' is '4'

Step-by-step explanation:

given that:

A(1,3) ,B (-1,2) ,C(2,5),D (x,4) are the vertices of a parallelogram ABCD .

we have to find the value of 'x'

also , AC and BD are diagonal of given parallelogram with vertices ABCD.

we know that: diagonals of a parallelogram intersect at a point.

let the intersection point be O(P, Q)

P and Q are coordinates of intersection.

formula to find coordinates of intersection of diagonals AC and BD is:

P = (x₁ + x₂)/2

Q = (y₁ + y₂)/2

where x₁=x-coordinate of A = 1

x₂=x-coordinate of C = 2

y₁=y-coordinate of A = 3

y₂ = y-coordinate of C = 5

so P = (1 + 2)/2 = 3/2

Q = (3 + 5)/2 = 8/2 = 4

this also satisfies with the diagonal BD

P = 3/2 = (-1 + x)/2

x - 1 = 3

x = 4

value of 'x' is '4'