Math, asked by parassingh8683, 1 month ago

If A(1, 3), B(-1, 3), C(2, 5) and D (x, 5) are the vertices of a parallelogram ABCD, then the value of x is :

3
4
5
None of these

Answers

Answered by Anonymous
7

Given: A(1, 3), B(-1, 3), C(2, 5) and D (x, 5) are the vertices of a parallelogram ABCD

To find: Value of x

Solution: We are given 4 vertices of a parallelogram ABCD.

Let the diagonals be AC and BD

We also know that diagonals of a parallelogram bisect each other.

Let the point where the diagonals AC and BD bisect be O

First let's find the coordinates of O (X, Y) through diagonal AC

X= 1+2/2= 3/2

Y= 3+5/2= 4

with diagonal BD

X= -1+x/2= 3/2

x= 5

Y= 3+5/2= 4

therefore, the value of x will be 5.

Answered by 20Abhiram20
0

Answer:

Answer

4

3.0

Given: A(1, 3), B(-1, 3), C(2, 5) and D (x, 5) are

the vertices of a parallelogram ABCD

To find: Value of x

Solution: We are given 4 vertices of a parallelogram ABCD.

Let the diagonals be AC and BD

We also know that diag of a

parallelogram bisect each other.

Let the point where the diagonals AC and BD bisect be O

First let's find the coordinates of O (X, Y)

through diagonal AC

X= 1+2/2= 3/2

Y= 3+5/2= 4

with diagonal BD

X=-1+x/2= 3/2

x = 5

Y= 3+5/2= 4

therefore, the value of x will be 5.

Step-by-step explanation:

HOPE THIS HELPS U

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