Math, asked by mhemangi934, 12 hours ago

If a= 1/3- root 11 and b =1/a find a^2- b^2

Answers

Answered by ro11111
0

Answer:

a =√11/3b = 1/a = 1/(√11/3) = 3/√11a2 - b2 = (√11/3)2 -(3/√11)2 ={(√11)2/(3)2} - {(3)2/(√11)2}= (11/9) - (9/11) = (121-81)/99= 40/99

this the answer

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