If (a+1),3a,(4a+2) are in ap. Find the 7th term of the series. HURRYYYYYY Up.
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Answered by
6
t7=a+1+(7-1)2a+1
=a+1+14a+7-2a-1
=13a+7
=a+1+14a+7-2a-1
=13a+7
Answered by
6
if the series is in ap the difference between the terms should be the same.
so 3a-(a+1)=4a+2-3a
so a=3
the series will be 4,9,14,19,24,29,34
7th term is 34,
or u can use 7th term= (x)+(n-1)*d
where x is the first term here a+1 which is 4
n=7
d=5
so 3a-(a+1)=4a+2-3a
so a=3
the series will be 4,9,14,19,24,29,34
7th term is 34,
or u can use 7th term= (x)+(n-1)*d
where x is the first term here a+1 which is 4
n=7
d=5
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