If a -1/4 =4 then prove that a^3 - 1/a^3 =76
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Step-by-step explanation:
I believe your Question is,
"If (a - (1/a)) = 4, then prove that, (a³ - (1/a³)) = 76
We have,
(a - (1/a)) = 4
Now,
We know that,
(a - b)³ = a³ - 3ab(a - b) - b³
So, using the identity,
(a - (1/a))³ = 4³
a³ - 3(a)(1/a)(a - (1/a)) - (1/a)³
Here,
a × (1/a) = 1 [ a cancels out]
a - (1/a) = 4 [Given]
So,
a³ - 3(4) - (1³/a³) = 64
a³ - 12 - (1/a³) = 64
a³ - (1/a³) = 64 + 12
a³ - (1/a³) = 76
Hence proved
Hope it helped and believing you understood it........All the best.
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