if A={1, 4}and B={x:x belongs to natural number, x^2-4=0}find a cross b
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given :
A = {1,4}
B = {x: x £N , x^2-4=0}
x^2-4=0
=) x^2 = 4
=) x = 2
(WKT Sq.root of 4= +2,-2;
but -2 have to be neglected,
coz -2 is not a natural number)
therefore, B = { 2 }
A × B = { 1,4 } × { 2 }
A × B = { (1,2), (4,2)}
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