Question

If a =

1

5√2+7

and b =

1

3−2√2

, find the value of a2 + b2 – ab.​

Answer 1

Answer:

a= 5√2+7

a²= (5√2+7)²

a²= (5√2)²+(7)²+2(35√2)

a²= 50+49+70√2

a²= 99+70√2

b= 3-2√2

b²= (3-2√2)²

b²= (3)²+(2√2)²-2(6√2)

b²= 9+8-12√2

b²= 17-12√2

ab= 3(5√2+7)-2(5√2+7)

= 15√2+21-10√2-14

= 5√2+7

now putting together in a²+b²-ab

Step-by-step explanation:

a=