Question

If a=1/7-4√3 and b=1/7+4√3 then find the value of a a square +b square

Answer 1

Step-by-step explanation:

given,

a=1/7-4√3

b=1/7+4√3

a^2=[1/7-4√3]^2

we know that,

[a-b]^2=a^2+b^2-2ab

=(1/7)^2+(4√3)^2-2*(1/7)*(4√3)

=(1/49)+(16*3)-2(4√3/7)

a^2=1/49+48-8√3/7

b^2=[1/7+4√3]^2

similarly,(a+b)^2=a^2+b^2+2ab

=1/49+48+8√3/7

a^2+b^2=1/49+48-8√3/7+1/49+48

+8√3/7

=2/49+96

=(2+4704)/96

=4706/96