If a = 1/7-4√3 and b=1/7+4√3, then find the value of a²+b²
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Answer:
96(2/49)
Step-by-step explanation:
ab=(1/7-4√3)(1/7+4√3)
=(1/7)^2-(4√3)^2
=1/49-48
a+b=2/7
(a^2+b^2)=(a+b)^2-2ab
=4/49-2/49+96
=2/49+96
=96(2/49)
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