Question

If a = 1/7-4√3 and b=1/7+4√3, then find the value of: (i) a^2+b^2 (ii) a^3+b^3​

Answer 1

Step-by-step explanation:

from the given a = root 3 / 9 ;b = root 3/33

a2 + b2 = 3/81 + 3 /1089 = 0.0027

a3 + b3 = square root of 3 = 1.71 so cube root of 1.71/9 =

= 1.2 / 2.08 + 1.2/3.2 = 0.55 (i got cube root

of 33

plz thx and flower me

Answer 2

Answer:

(I) 0.05

(ii) 41.73

Step-by-step explanation:

(I) a²+b²=(1/7-4✓3)²+(1/7+4✓3)²

= ( 1/49 - 48) +(1/49 + 48)

=(1-2352/49) + (1+2353/49)

= -47.97 +48.02

= 0.05

(ii) a³+b³=(1/7-4✓3)³+(1/7+4✓3)³

= (-6.78)³ +(7.07)³

= -311.66 +353.39

= 41.73