Question

if a = 1/7 and b = 8/14 find the value of a - b and b - a . State whether a-b and b-a are equal or not ​

Answer 1

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➪We know that sum of three angles of a triangle is 180

➪Hence ∠A+∠B+∠C=180°

➪or A+B+C=180°

➪B+C=180° −A

➪Multiply both sides by 1/2

➪1/2 (B+C) = 1/2 (180° − A)

➪1/2 (B + C) = 90° - A/2...(1)

➪Now 1/2 (B+C)

➪Taking sine of this angle

➪sin (B + C /2)

➪[B + C /2 = 90° - A/2]

➪sin(90°-A/2)

➪cos A/2 [sin(90° - θ ) = cos θ]

➪Hence sin( B + C/2 )=cos A/2 proved

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Answer 2

Step-by-step explanation:

$a - b \: = \: \frac{1}{7} - \frac{8}{14} = \frac{2 - 8}{14} = \frac{ - 6}{14} = \frac{ - 3}{7}$

$b - a \: = \: \frac{8}{14} - \frac{1}{7} = \frac{8 - 2}{14} = \frac{6}{14} = \frac{3}{7}$

Therefore a-b is not equal to b-a as sign is opposite. one is positive and other is negative

Hope it helps you

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