if a+1/a =1 then find the value of a^3+1
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Answer:
a+1/a = 3. eq(1)
taking cube on both sides then eq(1) becomes
(a+1/a)^3 = 3^3
by using the formula
[ (a + b)^3 = a3 + 3ab(a+b) + b3 ]
a3 + 3(a)(1/a)(a+1/a) + (1/a)^3 = 9
a3 + b3 +(a+1/a) = 9
As we know that. (a+1/a)= 3
so,
a3 + 1/a3 +3(3) = 9
a3 +1/a3 + 9 = 9
a3+1/a3 = 9-9
a3+1/a3 = 0 ✓✓ [SOLVED]
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Step-by-step explanation:
a+1/a=1 find the value of a3 +1
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