if a+1/a=1 then the value of a^33+8.
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This question of complex no.s
so ,
a+ 1/a=1
a^2-a+1=0
roots of this equation will be(1+√-3)/2 and (1-√-3)/2
means -w and -w^2 (here w is omega)
so we know that
w^3=1
when a= -w
a^33= (-w)^33 = - w^33=-(w^3)^11=-1
similarly when a=-w^2
a^33=-(w^2)^33 =-1
so from both , we get a^33 =-1
Answer is -1+8=7
so ,
a+ 1/a=1
a^2-a+1=0
roots of this equation will be(1+√-3)/2 and (1-√-3)/2
means -w and -w^2 (here w is omega)
so we know that
w^3=1
when a= -w
a^33= (-w)^33 = - w^33=-(w^3)^11=-1
similarly when a=-w^2
a^33=-(w^2)^33 =-1
so from both , we get a^33 =-1
Answer is -1+8=7
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