Question

If (a+1/a)^2=9 then show that a^3+1/a^3=0
a)10√3/3 b)3√3
c)18 d)7√7

Answer 1

Step-by-step explanation:

(a+1/a)²=9...........(a+1/a)=3

a²+1/a²+2(a)(1/a)=9

a²+1/a²+2=9

a²+1/a²=7

a³+1/a³

(a+1/a)(a²+1/a²-(a)(1/a))

3(7-1)

3(6)

18