If a + 1/ a = (3)^1/3 then show that a^3 1/a^3 =0
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Step-by-step explanation:
(a+1/a)^2 = 3
a+1/a = root3
Cubing both sides, we get
a^3 + 1/a^3 + 3(a+1/a) =3root3 [by using formula: (a+b)^3= a^3 +b^3 +3ab(a+b)]
a^3 + 1/a^3 + 3root3(value of a+1/a) = 3root3
a^3 +1/a^3+3root3-3root3=0
a^3+1/a^3= 0(as 3root3 of different signs cancel each other)
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