Math, asked by NafishaAly, 7 months ago

If a + 1/ a = (3)^1/3 then show that a^3 1/a^3 =0​

Answers

Answered by Anonymous
0

Answer:

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Step-by-step explanation:

(a+1/a)^2 = 3

a+1/a = root3

Cubing both sides, we get

a^3 + 1/a^3 + 3(a+1/a) =3root3 [by using formula: (a+b)^3= a^3 +b^3 +3ab(a+b)]

a^3 + 1/a^3 + 3root3(value of a+1/a) = 3root3

a^3 +1/a^3+3root3-3root3=0

a^3+1/a^3= 0(as 3root3 of different signs cancel each other)

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