If (a+1/a)^3,and a≠0,then find the value of (a^3+1/a^3)
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bro u forget to give the value of (a+1/a)³
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Answer:
3 - 3∛3
(This is a corrected version of answer given before!)
Step-by-step explanation:
The key fact that we need is (x+y)³ = x³ + 3x²y + 3xy² + y³.
Putting x=a and y=1/a gives
(a+1/a)³ = a³ + 3(a²)(1/a) + 3(a)(1/a²) + 1/a³
= (a³ + 1/a³) + 3(a + 1/a)
⇒ a³ + 1/a³ = (a+1/a)³ - 3(a+1/a)
= 3 - 3∛3
Hope that helps!
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