If a+1/a=3, find the value of a5+1/a5
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Solution :-
→ a + 1/a = 3
squaring both sides ,
→ (a + 1/a)² = 3²
→ a² + 1/a² + 2 * a * 1/a = 9
→ (a² + 1/a)² = 9 - 2 = 7
again,
→ a + 1/a = 3
cubing both sides ,
→ (a + 1/a)³ = 3³
→ a³ + 1/a³ + 3 * a * 1/a * (a + 1/a) = 27
→ (a³ + 1/a³) + 3 * 3 = 27
→ (a³ + 1/a³) = 27 - 9 = 18 .
then,
→ (a⁵ + 1/a⁵) = (a² + 1/a)² * (a³ + 1/a³) - (a + 1/a)
putting all values we get,
→ (a⁵ + 1/a⁵) = 7 * 18 - 3
→ (a⁵ + 1/a⁵) = 126 - 3
→ (a⁵ + 1/a⁵) = 123 (Ans.)
Learn more :-
JEE mains Question :-
https://brainly.in/question/22246812
. Find all the zeroes of the polynomial x4
– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.
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