Question

if a+1/a=34 then find the value of √a+1/√a​

Answer 1

Answer:

iven: a+\dfrac{1}{a}=34

To find: The value of \sqrt{a} +\dfrac{1}{\sqrt{a} }

Now as we know

(a+b)^2 = a^2+b^2+2ab

So we have

(\sqrt{a} +\dfrac{1}{\sqrt{a} })^2=(\sqrt{a} )^2+(\dfrac{1}{\sqrt{a} })^2+2\times\sqrt{a} \times \dfrac{1}{\sqrt{a} }\\\\\Rightarrow (\sqrt{a} +\dfrac{1}{\sqrt{a} })^2= a+\dfrac{1}{a} +2

substitution the value of  a+\dfrac{1}{a}=34

we get

\\\\\Rightarrow (\sqrt{a} +\dfrac{1}{\sqrt{a} } )= 32+2\\\\\Rightarrow  (\sqrt{a} +\dfrac{1}{\sqrt{a} } )=36\\\\\Rightarrow \sqrt{a} +\dfrac{1}{\sqrt{a} } =\sqrt{36} \\\\\Rightarrow \sqrt{a} +\dfrac{1}{\sqrt{a} } =6

Hence ,the value of \sqrt{a} +\dfrac{1}{\sqrt{a} }  is 6

Answer 2

Answer:

answer for the given problem is given