Math, asked by rudran, 1 year ago

If a-1/a=4, find the value of a³-1/a³

Answers

Answered by benhurmuthu
16

Step-by-step explanation:

a-1/a=4

square on both sides

(a-1/a)²=4²

a²+1/a²-2a.1/a=16

a²+1/a²-2=16

a²+1/a²=14

a³-b³=(a-b)(a²+b²+ab)

using this formula we get

a³-1/a³ = (a-1/a)(a²+1/a²+a.1/a)

=4(14+1)

=4*15=60

Answered by bhumi996
3

a³- 1/a³ = 60

given,

a-1/a = 4

squaring both side

(a-1/a)² = 4²

a²+1/a²-2(a) (1/a) = 16

a²+1/a²-2=16

a²+1/a²=16+2

a²+1/a²= 18

a³-b³=(a-b) (a²+b²+ab)

a³-1/a³=(a-1/a) (a²+1/a²+a×1/a)

=4(14+1)

=4×15

=60

Similar questions