Math, asked by vinodsharma88350, 7 months ago


if a+1/a=5 and a-1/a=3, find a²+1/a²=​

Answers

Answered by prince5132
8

CASE 1 :-

GIVEN :-

 \\  \longrightarrow \: \sf a +  \dfrac{1}{a} = 5  \\ \\

TO FIND :-

 \\  \longrightarrow \: \sf value \: of \:  \: a ^{2}  +  \dfrac{1}{a ^{2} }  \\ \\

SOLUTION :-

   \\  : \implies \: \sf a +  \dfrac{1}{a} = 5  \\  \\ \red{\bigstar} \blue{ \sf \: Squaring  \: \:  Both \:  \:  sides } \\  \\  : \implies \: \sf  \bigg(a +  \dfrac{1}{a}  \bigg)^{2} = (5) ^{2} \\  \\  \red{ \bigstar} \blue{ \sf \: Identity \to (a + b)^{2} = a^{2} + b^{2} + 2 ab}  \\  \\  : \implies \: \sf  a^{2}  +   \bigg(\dfrac{1}{ a}  \bigg) ^{2}  + 2 \times  \cancel a \times  \dfrac{1}{ \cancel a}  = 25 \\  \\   : \implies \: \sf a ^{2}  +  \dfrac{1}{a ^{2} }  + 2 = 25 \\  \\   : \implies \: \sf a ^{2}  +  \dfrac{1}{a^{2} }  = 25 - 2 \\  \\: \implies \: \sf a ^{2}  +  \dfrac{1}{a^{2} }  = 23 \\  \\ \red{ : \implies} \:  \underline{ \boxed{ \red{\sf a ^{2}  +  \dfrac{1}{a^{2} } = 23 }}}  \\  \\

❏ Hence the value of a² + 1/a² = 23.

  \\ \rule{300}{2.5} \\

CASE 2 :-

GIVEN :-

 \\  \longrightarrow \: \sf a  -   \dfrac{1}{a} = 3 \\ \\

TO FIND :-

 \\  \longrightarrow \: \sf value \: of \:  \: a ^{2}  +  \dfrac{1}{a ^{2} }  \\ \\

SOLUTION :-

 \\    : \implies \: \sf a  -   \dfrac{1}{a} = 3 \\  \\ \red{\bigstar} \blue{ \sf \: Squaring  \: \:  Both \:  \:  sides } \\  \\  : \implies \: \sf  \bigg(a  -   \dfrac{1}{a}  \bigg)^{2} = (3) ^{2} \\  \\  \red{ \bigstar} \blue{ \sf \: Identity \to (a  -  b)^{2} = a^{2} + b^{2}  - 2 ab}  \\  \\  : \implies \: \sf  a^{2}  +   \bigg(\dfrac{1}{ a}  \bigg) ^{2}   - 2 \times  \cancel a \times  \dfrac{1}{ \cancel a}  = 9 \\  \\   : \implies \: \sf a ^{2}  +  \dfrac{1}{a ^{2} }   - 2 = 9 \\  \\   : \implies \: \sf a ^{2}    +   \dfrac{1}{a^{2} }  = 9  + 2 \\  \\: \implies \: \sf a ^{2}  +  \dfrac{1}{a^{2} }  = 11 \\  \\ \red{ : \implies} \:  \underline{ \boxed{ \red{\sf a ^{2}  +  \dfrac{1}{a^{2} } = 11 }}}  \\  \\

❏ Hence the value of a² + 1/a² = 11.


Anonymous: Awesome Written.
Answered by adhyayan56
0

Step-by-step explanation:

{\huge{\underline{\boxed{\mathbb{{question}}}}}}

•if a+1/a=5 and a-1/a=3, find a²+1/a²

Given:

a+1/a=5

a-1/a=3

To find:

a²+1/a²

Answer:

  • formula used

(a-b)²=a²+b²-2ab

___________________________________________

a-1/a=5

on squaring (²) both sides

(a-1/a)²=(3)²

a²+1/a²-2=9

a²+1/a²=9+2

a²+1/a²=11

___________________________________________

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