Question

if a-1/a=8 and a is not equal to zero.Find a+1/a or a2-1/a2​

Answer 1

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$a-\frac{1}{a} = 8$

$(a-\frac{1}{a})^{2} =a^{2} + \frac{1}{a^{2} } -2*a*\frac{1}{a}$

$8^{2} = a^{2} + \frac{1}{a^{2} } -2$

$64 = a^{2} + \frac{1}{a^{2} }-2$

$a^{2} + \frac{1}{a^{2} } = 64+2 = 66$

$(a+\frac{1}{a})^{2}= a^{2} + \frac{1}{a^{2} }+2$

$(a + \frac{1}{a })^{2} = 66+2$

$a + \frac{1}{a } = \sqrt{68}$

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Answer 2

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Here is ur answer........

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