If a+1/a =p and a-1/a=q,find the relation between p and q.
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Answered by
9
a+1/a = p
squaring both sides,
(a+1/a)² = p²
⇒(a²+1/a² +2) = p²
subtracting both sides 4,
(a²+1/a²+2) -4 = p²-4
⇒(a²+1/a²-2) = p² -4
⇒(a-1/a)² = p² -4
⇒q² = p² - 4
⇒p² - q² = 4
This is the required relation.
squaring both sides,
(a+1/a)² = p²
⇒(a²+1/a² +2) = p²
subtracting both sides 4,
(a²+1/a²+2) -4 = p²-4
⇒(a²+1/a²-2) = p² -4
⇒(a-1/a)² = p² -4
⇒q² = p² - 4
⇒p² - q² = 4
This is the required relation.
Answered by
3
Answer:
It is given that,
a+1/a=p and a−1/a=q
so,
(a+1/a)
2
−(a−1/a)
2
=4(a)(1/a)
=4
By substituting the values, we get
p
2
−q
2
=4
Hence the relation between p and q is that p
2
−q
2
=4.
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