if a+¹/a= then a³+1=
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Given : a + 1/a) = 1
To Find : a³ + 1
Solution:
a + 1/a = 1
=> a² + 1 = a
=> a² - a + 1 = 0
a³ + b³ = (a + b)(a² -ab + b²)
a = a and b = 1
a³ + 1 = (a + 1)(a² - a + 1)
substituting a² - a + 1 = 0
=> a³ + 1 = (a + 1)0
=> a³ + 1 = 0
Hence if a + 1/a = 1 then a³ + 1 = 0
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If a + b + c = 1, a2+b2+c2=9, a3+b3+c3=1 find 1/a + 1/b + 1/c ...
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