Math, asked by krishanmongia99, 4 months ago

If a=-1 and b=3, the value of a³+a²b+ab²+b³ is please tell fast their is my paper​


krishanmongia99: please tell fast

Answers

Answered by anubharti42439
6

a³ +a² b + ab² +b³

= (-1)³ + (-1)² (3) + (-1)(3)² + (3)³

= -1 + (-3) + (-9) + 27

= -1 - 3 - 9 + 27

= -4 + 18

= 14

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Answered by khashrul
0

Answer:

a^3 + a^2b + ab^2 + b^3 = 20

Step-by-step explanation:

a^3 + a^2b + ab^2 + b^3

=a^2(a + b) + b^2(a + b)

=(a + b)(a^2 + b^2)

=(-1 + 3)[(-1)(-1) + (3)(3)]

=2[1 + 9]

=2x10

=20

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