If a=1 and d=3, then find S10
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Answer:
Sn = n/2 [2a + (n-1) d]
S10 = 10/2 [2*1 + (10-1) 3 ]
S10 = 5 [2 + (9) 3 ]
S10 = 5 [2+27]
S10 = 5*29
S10 = 145
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