Question

If a = – 1, b = 0 and c = 1, find the value of the given expression. 3 3abc2 + 5ac – 2a2 bc

Answer 1

Answer:

$3ab {c}^{2} + 5ac - 2 {a}^{2} bc \\ = 3( - 1)(0)( {1}^{2} ) + 5( - 1)(1) - 2( { - 1)}^{2} (0)(1) \\ = 0 - 5 - 0 \\ = - 5$

Answer 2

Step-by-step explanation:

3abc 2+5ac−2a 2

bc=3(−1)(0)(1

2

)+5(−1)(1)−2(−1)

2

(0)(1)

=0−5−0

=−5