Question

If a=1, b=-1 c=0 find the value of (a2-b2) + (c2-b2)
Please do it

Answer 1

Answer:

=(a2-b2)+(c2-b2)

=(1-1+2)+(02+1*2)

=0-2+2+2

=2 Answer

Answer 2

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:

Given :

a=1,b= -1 & c=0

To Find:

$( {a}^{2} - {b}^{2} )$

$( {c}^{2} - {b}^{2} )$

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Identity used here :

$\bold{\boxed{(a + b)(a - b) = {a}^{2} - {b}^{2}}}$

$= > {a}^{2} - {b}^{2} = (a + b)(a - b)$

$= [1( + ) - 1][(1 - ( - 1)]$

$= > (1 - 1)(1 + 1) = 0 \times 2 ={\bold{\red{ 0}}}$

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$= > {c}^{2} - {b}^{2} = (c + b)(c - b)$

$= [0 + ( - 1)][(0 - ( - 1)]$

$= (0 - 1)(0 + 1) = - 1(1) = {\bold{\red{- 1}}}$

Now adding both :-

$\huge\bold{\red{0+(-1)}}$$\huge\bold{=-1}$