Question

If a=1,b=10,c=100 and d=1000 then (a+b+c-d)+(a+b-c+d)+(a-b+c+d)+(-a+b+c+d) is equal to ________________

Answer 1

Answer:

2222 is the answer

Step-by-step explanation:

by putting all the value in the equation :

(1+10+100-1000)+(1+10-100+1000)+(1-10+100+1000)+(-1+10+100+1000)

this equation is equal to 2222