Question

If a=1,b=10,c=100 and d=1000 then (a+b+c-d)+(a+b-c+d)+(a-b+c+d)+(-a+b+c+d) is equal to ________________

Answer 1

Answer:

4444

Step-by-step explanation:

just substitute with the variables inside the bracket

so here

a=1

b=10

c=100

d=1000

(a+b+c+d) +(a+b+c+d)+(a+b+c+d)+(a+b+c+d)

=(1+10+100+1000)+(1+10+100+1000)+(1+10+100+1000)+(1+10+100+1000)

= 1111+1111+1111+1111

= 4444

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