If a = 1, b = - 2 and c = 3, find the value of
a² +4b-c
a² – 2b²+4c
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Answer:
a = 1, b = –2, c = 3
i) a²+4b–c = (1)²+4(–2)–3
= 1–8–3
= –10
ii) a²–2b²+4c = (1)²–2(–2)²+4(3)
= 1–2×4+12
= 1–8+12
= 5
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