Question

If a = 1, b = - 2 and c = 3, find the value of
a² +4b-c
a² – 2b²+4c​

Answer 1

Answer:

a = 1, b = –2, c = 3

i) a²+4b–c = (1)²+4(–2)–3

= 1–8–3

= –10

ii) a²–2b²+4c = (1)²–2(–2)²+4(3)

= 1–2×4+12

= 1–8+12

= 5