Question

If a = 1, b=-2 and c = 3 then find the value of a^2 + b^2 + c^2 + ab + bc +ca​

Answer 1

Answer:

6 :

explaination :

Formula,

(a+b+c)2=a2+b2+c2+2ab+2bc+2ca

⇒(a+b+c)2=a2+b2+c2+2(ab+bc+ca)

Given,

ab+bc+ca=10,a2+b2+c2=16

⇒(a+b+c)2 =16+2(10)

a+b+c= √16+20=6

√\_________anushka ❤❤

Answer 2

Answer:

9

Step-by-step explanation:

=1^2+(-2)^2+3^2+1X(-2)+(-2)X3+3X1

=1+4+9+(-2)+(-6)+3

=17+[(-2)+(-6)]

=17 + (-2-6)

=17+(-8)

=17-8

=9