Question

if a=1,b=-2 and c=3 then find the value of a²+b²+c²+ab+bc+ca​

Answer 1

Answer:

1

Step-by-step explanation:

1^2 +-2^2 +-2 +-6 +3

2+4=6

6+-2= 4

4+-6=-2

-2 +3 = 1

Answer 2

Answer:

${a}^{2} + {b +}^{2} + {c}^{2} + ab + bc + ca$

By adding the numbers in the equation.

1² + -2² + 3² + ( 1 × -2 ) + ( -2 × 3 ) + ( 3 × 1 )

1 + 4 + 9 + ( -2 ) + ( -6 ) + ( 3 )

14 + ( -2 ) + ( -6 ) + ( 3 )

14 + 3 + ( -2 ) + ( -6 )

17 - 8

9.