Question

If a=1,b=-2,c=-1 show that 7a+b+c=2abc

Answer 1

Answer:

Given,

$a = 1$

$b = - 2$

$c = - 1$

$\: \: \: \: \: \: \: 7a + b + c = 2abc$

$= > (7 \times 1) + (- 2) + ( - 1) = 2 \\ \: \: \: \: \: \: \: \ \times 1 \times ( - 2) \times ( - 1)$

$= > 7 - 2 - 1 = 4$

$= > 7 - 3 = 4$

$= > 4 = 4$

Answer 2

Step-by-step explanation:

given

a =1

b = -2

c = -1

as per condition

$7a \: + b + c = 2abc$

now put the values

$7 \times 1 + ( - 2) + ( - 1) = 2 \times 1 \times - 2 \times - 1$

now

$7 - 3 = 2 \times 2$

$4 = 4$

hence its prove that.....