Question

if a=1 b=2 c= -3 find the value of a²+b²+c²-2ab+2bc-2ac​

Answer 1

Answer:

$a = 1 \\ b = 2 \\ c = 3 \\ \\ = {a}^{2} + {b}^{2} + {c}^{2} - 2ab - 2ac \\ = {(1)}^{2} + {(2)}^{2} + {(3)}^{2} - (2 \times 1 \times 2) - (2 \times 1 \times 3) \\ = 1 + 4 + 9 + 4 + 6 \\ = 14$

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